Question :
51) Rob scored exactly in the middle of his class : 1184137
51) Rob scored exactly in the middle of his class on the social studies exam. A valid interpretation of Rob’s performance is that he scored exactly at the
A) center of a symmetrical frequency distribution.
B) mean of the class.
C) median of the class.
D) mode of the class.
52) What is the median for the following set of scores? Scores: 66, 66, 74, 96, 98
A) 66
B) 74
C) 78
D) 80
53) The relationship between the standard deviation and test scores is that the larger the standard deviation, the
A) greater the variability in the distribution.
B) higher the central tendency.
C) lower the variability in the distribution.
D) narrower the distribution of scores.
54) A standard deviation is a measure of
A) how well the students met the tested objectives.
B) the distance between the median and the extreme scores.
C) the spread of scores around the mean.
D) the level of validity for the test.
55) The Algebra I class mean and standard deviation are 80 and 10, respectively. The Biology II class mean and standard deviation are 79 and 4, respectively. Kristen scored 90 in Algebra I and 87 in Biology II. The most valid conclusion to be drawn from these data is that Kristen
A) scored better relative to her class in Algebra I than in Biology II.
B) scored better relative to her class in Biology II than in Algebra I.
C) should earn an A in Algebra I and a B in Biology II.
D) would be served better by criterion-referenced grading than by norm-referenced grading in both courses.
56) Mr. Skiebert gave the same physics test to each of his three senior classes. Analysis of the data revealed the following descriptive statistics:
Class
Mean
Standard Deviation
One
59
7.5
Two
68
6.2
Three
62
6.9
Compared to the two other classes, Mr. Skiebert can infer that students in Class One exhibit
A) a narrow distribution of scores.
B) greater variability.
C) higher central tendency.
D) lower variability.
57) On the midterm, Ms. Gomez’ first-period class had a mean of 79.5 and a standard deviation of 5. Her third-period class had a mean of 81.7 and a standard deviation of 17. Given only this information, what inference can be made?
A) The first period is more difficult to teach than third period.
B) The midterm was probably too difficult for both classes.
C) The third period is more difficult to teach than first period.
D) The two classes seem to be fairly equal in abilities.
58) Approximately what percentage of the scores in a normal distribution is higher than one standard deviation above the mean?
A) 2.5 percent
B) 16 percent
C) 34 percent
D) 68 percent
59) In a normal distribution of scores, approximately what percent of the z-scores will be negative?
A) 0
B) 25
C) 50
D) Cannot determine from the information given.
60) In a normal distribution, which one of the following measures of central tendency will have the highest value?
A) Mean
B) Median
C) Mode
D) The central tendencies will be equal.