Name:
College ID:
Thomas Edison State College
General Chemistry II with Labs (CHE-122)
Section no.:
Semester and year:
Laboratory Assignment for Module 3: Reaction Rates
(eScience Lab 4 [16])
Table 1. 10 mL Undiluted IKI and 5 mL 3% H2O2
Water displaced in milliliters |
Time in seconds |
2 mL |
|
4 mL |
|
6 mL |
|
8 mL |
|
10 mL |
|
12 mL |
|
14 mL |
|
16 mL |
|
18 mL |
|
20 mL |
|
22 mL |
|
Table 2. 10 mL 0.5–1.0% IKI and 5 mL 3% H2O2
Water displaced in milliliters |
Time in seconds |
2 mL |
|
4 mL |
|
6 mL |
|
8 mL |
|
10 mL |
|
12 mL |
|
14 mL |
|
16 mL |
|
18 mL |
|
20 mL |
|
22 mL |
|
Table 3. 10 mL 0.5–1.0% IKI and 5 mL 2.25% H2O2
Water displaced in milliters |
Time in seconds |
2 mL |
|
4 mL |
|
6 mL |
|
8 mL |
|
10 mL |
|
12 mL |
|
14 mL |
|
16 mL |
|
18 mL |
|
20 mL |
|
22 mL |
|
III. CALCULATIONS (20 POINTS)
Table 1: 10 mL Undiluted IKI and 5 mL 3% H2O2
Slope:
Inverse Slope:
Table 2: 10 mL 0.5–1.0% IKI and 5 mL 3% H2O2
Slope:
Inverse Slope:
Table 3:10 mL 0.5–1.0% IKI and 5 mL 2.25% H2O2
Slope:
Inverse Slope:
Order of H2O2:
Order of IKI:
Rate law constant:
*Show Calculations and Include Graphs
IV. RESULTS (15 POINTS)
Overall rate law:
1. How many grams of IKI (iodine-potassium iodide; molar mass = 166.0 g/mol) would it take to obtain a 100.0 mL solution of 0.300 M IKI? How many grams of IKI would it take to create a 100.0 mL solution of 0.600 M IKI? (6 points)
2. What is the molarity of 100.0 mL of a 3.0% H2O2 (mass/volume) solution? What is the molarity of 100.0 mL of a 2.25% H2O2 (mass/volume) solution? (6 points)
3. When finding the order of H2O2, why was Trial 1 and Trial 3 used? (6 points)
4. When finding the order of IKI, why was Trial 1 and Trial 2 used? (6 points)
5. How does temperature affect the reaction rate? Explain in terms of the collision theory.
(6 points)
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